For a quick link to the logic game: https://7sage.com/lsat_explanations/lsat-33-section-4-game-2/
I am so confused with question 9. I understand the logic 7Sage uses to illustrate how if G and W are out then H, J, M, and S can be in. With that logic, if H, J, M are in, then any sufficient conditions could also be in, (in this case also S), and therefore count a total of 4 in. But with this logic of making all sufficient conditions free floaters, couldn’t you also do the following to justify there being 6 in the “in” category?
/S —> J —> H –> /G —> /W
(and then run the contrapositive)
W —> G —> /H —> /J —> S
In this case, all you could say is S is in, and therefore, let all other letters be sufficient conditions, and therefore free floaters, and therefore put them all in the “in” category, and therefore count a total of 6 as “in”.
How could this alternative possibility not be wrong?!?!?!?!?!?!?
Sufficient and necessary conditions made so much sense up until this one point.